245(t)=-16t^2+136t+5

Solution for 245(t)=-16t^2+136t+5 equation:

245(t)=-16t^2+136t+5

We move all terms to the left:

245(t)-(-16t^2+136t+5)=0

We get rid of parentheses

16t^2-136t+245t-5=0

We add all the numbers together, and all the variables

16t^2+109t-5=0

a = 16; b = 109; c = -5;
Δ = b2-4ac
Δ = 1092-4·16·(-5)
Δ = 12201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12201}=\sqrt{49*249}=\sqrt{49}*\sqrt{249}=7\sqrt{249}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(109)-7\sqrt{249}}{2*16}=\frac{-109-7\sqrt{249}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(109)+7\sqrt{249}}{2*16}=\frac{-109+7\sqrt{249}}{32}
$